| Construction start | 12th October 2010 |
| Construction end | 8th January 2012 |
| Number of networks | 3 |
| Number of lifts | 11 |
| Number of paths | 17 |
If that video doesn't work please go here: http://www.youtube.com/watch?v=cTCSmDef5Q4
This is Catastropha, one of the the largest ball machine I have constructed to date. It has 11 lifts and 17 paths.
The lifts are:
- Wheel lift with holes
- Alternator lift
- Double helix lift
- Ring lift
- Inverted chainsaw lift
- Small arm lift
- Pump list
- Mouse wheel lift
- Inverted motorized single helix lift
- Mill/Wheel lift
- Stair lift
| Path number | Network 1 | Network 2 | Network 3 |
| 1 | 1/3 | 0 | 0 |
| 2 | 0 | 0 | 1/6 |
| 3 | 0 | 0 | 1/6 |
| 4 | 0 | 1/3 | 0 |
| 5 | 1/4 | 0 | 0 |
| 6 | 0 | 0 | 1/4 |
| 7 | 0 | 1/4 | 0 |
| 8 | 0 | 0 | 1/4 |
| 9 | 0 | 1/6 | 0 |
| 11 | 1/6 | 0 | 0 |
| 12 | 1/6 | 0 | 0 |
| 13 | 0 | 1/6 | 0 |
| 14 | 0 | 1/12 | 0 |
| 15 | 1/12 | 0 | 0 |
| 16 | 0 | 0 | 1/12 |
| 17 | 0 | 0 | 1/12 |
| Sum it all up: | (1/3)+(1/4)+(1/6)+(1/6)+(1/12)=(4/12)+(3/12)+(2/12)+(2/12)+(1/12)=12/12=1 | (1/3)+(1/4)+(1/6)+(1/6)+(1/12)=(4/12)+(3/12)+(2/12)+(2/12)+(1/12)=12/12=1 | (1/6)+(1/6)+(1/4)+(1/4)+(1/12)+(1/12)=(2/12)+(2/12)+(3/12)+(3/12)+(1/12)+(1/12)=12/12=1 |
You might wonder why path 10 isn't in the table, that's because that it comes is so rare. To calculate that: It just happens when the four balls leave path eight, as it have to be four we have to do (1/4)*(1/4)=(1/16). And now only one of the balls go down that track so (1/16)*(1/4)=(1/64).
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